Question

16gm of oxygen and 3gm of hydrogen present in a vessel at 0°C and 760mm of the Hg pressure.volume of the vessel is​

Answer 1

mass of oxygen = 16gm

molecular mass of oxygen gas = 32g/mol

so, no of moles of O2 gas , n1 = 16/32 = 0.5

similarly, no of moles of H2 gas, n2 = given mass of H2/molecular mass of H2

= 3/2 = 1.5

so, total no of moles of gases , n = n1 + n2 = 0.5 + 1.5 = 2

applying formula, PV = nRT

here, P = 760mmHg or ~ 1atm

R = 0.0821 atm.Litre/mol.K

T = 273.15K

so, V = 2 × 0.0821 × 273.15/1

= 44.85123 ≈ 44.8 Litre

hence, volume of the vessel is 44.8 litre.

Answer 2

Answer:

44.8 l

Step-by-step explanation:

pv= nrt

760 mm of hg