Question

16k^2-36k-36
split the middle term

Answer 1

=16k²-36k-36
=4k²-9k-9(dividing all the terms by 4)
=4k²-(12-3)k-9
=4k²-12k+3k-9
=4k(k-3)+3(k-3)
=(4k+3)(k-3)
k=-3/4 or k=3

Answer 2

here
16k^2-36k-36=0
4(4k^2-9k-9)=0
4k^2-9k-9=0
4k^2-12k+3k-9=0
4k(k-3)+3(k-3)=0
(4k+3)(k-3)=0
k=3,-3/4

THANKS!