16kg block moving on a frictionless horizontal surface with a velocity of 5m/s compress an ideal spring and comes to sut. If the force constant of spring is 100N/m then how much is spring compressed
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Answer:
here is your answer
x= 1.6
Explanation:
1/2 kx2 = 1/2 mv2
1/2 X 100 X x2 = 1/2 X 16 X (4)2
50 X x2 = 256/2
x2 = 128/50
x2 = 2.56
x = 1.6
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