16p2- 49 is
a) (4p-7) (4p+7) b) (4p-7) (4p-7) c) (4p+7)(4p+7) d) (4p-49)+(4p-7)
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Answered by
2
Answer:
Productof(4p−7)(16p2+28p+49)
=(4p−7)[(4p)
2
+4p×7+7
2
]
=(4p)
3
−7
3
/*_______________
By Algebraic Identity :
\boxed { \pink { (a-b)(a^{2} + ab + b^{2} ) = a^{3} - b^{3} }}
(a−b)(a
2
+ab+b
2
)=a
3
−b
3
__________________*/
= 64p^{3} - 343=64p
3
−343
Therefore.,
\red{Product \:of \: (4p-7)(16p2+28p+49)}Productof(4p−7)(16p2+28p+49)
\green { = 64p^{3} - 343}=64p
3
−343
Answered by
3
Answer:
16p²-49
4p²-7²
(4p-7)(4p+7)
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