Question

16r²-40r+16=0
Find value of r
Can anyone help?​

Answer 1

Answer:

• 16$r^{2}$ - 40r + 16 = 0
• 16$r^{2}$ - 40r = -16
• 4r(4r - 10) = -16

• 4r - 10 = $\frac{-16}{4r}$

• 4r = $\frac{-4}{r}$+10
• r = $\frac{-4}{r}{+10}$ / 4