Math, asked by Dhruvsapra, 3 months ago

16r²-40r+16=0
Find value of r
Can anyone help?​

Answers

Answered by arnavagupta
0

Answer:

  • 16r^{2} - 40r + 16 = 0
  • 16r^{2} - 40r = -16
  • 4r(4r - 10) = -16
  • 4r - 10 = \frac{-16}{4r}
  • 4r = \frac{-4}{r}+10
  • r = \frac{-4}{r}{+10} / 4

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