Question

16th term of ap -3 -5 -7​

Answer 1

$\bf\red{QuestioN:-}$

16th term of AP -3, -5, -7​

$\bf\blue{AnsweR:-}$

The given AP = -3, -5 , -7...etc

• A = -3

• A₂ = A + d

As we know,

• A = -3, then,

• A₂ = -3 + d

• -5 = -3 + d

• d = -5 + 3 = -2

We need to find the 16th term of this AP,

• $\bf{A_{16}=A+15d}$

• $\bf{A_{16}=-3+15\times-2}$

Because we know the value of d = -2.

• $\bf{A_{16}=-3-30}$

• $\bf{A_{16}=-3+-30}$

• $\bf{A_{16}=-33}$

That is, the 16th term of this AP = -33!

Happy Learning!!

Answer 2

Answer:

$\huge\frak{ - 33}$

Step-by-step explanation:

.

Given -

A. P. (Arithmetic Progression) = -3, -5, -7....

.

To find -

16 th term (aⁿ)

.

Solution -

Here

$a_{1} = - 3 \\ a_{2} = - 5 \\ so \: common \: difference(d) = a_{2} - a_{1} \\ = - 5 - ( - 3) \\ = - 5 + 3 \\ = - 2$

By the formula ↓ we will find the 16th term

$a_{n} = a_{1} + (n - 1)d \\ (substitute \: the \: values) \\ = > 16th = - 3 + (16 - 1) \times - 2 \\ = > 16th = - 3 + (15 \times - 2) \\ = > 16th = - 3 - 30 \\ = > 16th = - 33$

Hence 16th term of this A. P. = -33

hope it helps.