Question

16th term of arithamatic sequance is -56and common difference -4 . find first term . form seqance. find the position of term .​

Answer 1

Answer:

first term is 4

Step-by-step explanation:

position is 1

Answer 2

Answer:

Step-by-step explanation:

$t_{16} =a+(16-1)d=-56\\a+15d=-56\\a+15(-4)=56\\a+60=56\\a=-4$

Sequence : -4,-8,-12,-16,-20...

Position = t_n = a+(n-1)d= -4+(n-1)-4 = -4-4n+4 = -4n