Question

16th term of arithamatic sequance is -56and common difference -4 . find first term . form seqance. find the position of term .​

Answer 1

Answer:

a=4

Step-by-step explanation:

Given:-

a₁₆=(-56),d=(-4)

To Find:-

a (1st term)

Formula Applied:-

aₙ=a+(n-1)d

Solution:-

a₁₆=a+(16-1)(-4)

-56=a+(15)(-4)

a=60-56

a=4

AP:- 4,0,(-4),(-8),(-12),...