16x^2+4x-2 find it
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Answer:
16x^2 + 4x - 2
16x^2 - 8x + 4x - 2
8x(2x -1) + 2(2x - 1)
(2x - 1)(8x + 2)
Answered by
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16x^2+4x-2
16x^2-8x+4x-2
8x(2x-1) +2(2x-1)
(2x-1) (8x+2)
2x-1=0 8x+2=0
2x=1 8x =-2
x=1/2 x=-1/4
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