16x^2+72x+81
Please solve fast
Answers
Answered by
37
hlo
16x² + 72x + 81
( 4x ) ² + 2 × 4x × 9 + ( 9 ) ²
a² + 2ab + b² = ( a + b ) ²
( 4x + 9 )²✔✔✔
hope it helps...
16x² + 72x + 81
( 4x ) ² + 2 × 4x × 9 + ( 9 ) ²
a² + 2ab + b² = ( a + b ) ²
( 4x + 9 )²✔✔✔
hope it helps...
Answered by
5
Answer:
Step-by-step explanation:
Rewrite
16
x
2
16x2 as
(
4
x
)
2
(4x)2.
(
4
x
)
2
−
72
x
+
81
(4x)2-72x+81
Rewrite
81
81 as
9
2
92.
(
4
x
)
2
−
72
x
+
9
2
(4x)2-72x+92
Check the middle term by multiplying
2
a
b
2ab and compare this result with the middle term in the original expression.
2
a
b
=
2
⋅
(
4
x
)
⋅
−
9
2ab=2⋅(4x)⋅-9
Simplify.
2
a
b
=
−
72
x
2ab=-72x
Factor using the perfect square trinomial rule
a
2
−
2
a
b
+
b
2
=
(
a
−
b
)
2
a2-2ab+b2=(a-b)2, where
a
=
4
x
a=4x and
b
=
−
9
b=-9.
(
4
x
−
9
)
2
(4x-9)2
1
6
x
2
−
7
2
x
+
8
1
|
|
16x2-72x+81||
x
x
x
2
x2
x
3
x3
()
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