Question

16x^2+8x+1 find the factor ​

Answer 1

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16x^2+8x+1 find the factor

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$➪16 {x}^{2} + 8x + 1$

$➪16 {x}^{2} + 4x + 4x + 1$

$➪4x(4x + 1) + 1(4x + 1)$

$➪(4x + 1)(4x + 1)$

$➪x = - \frac{ 1}{4} , - \frac{1}{4 }$

HOPE IT HELPS YOU..

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