Question

-16x^{2}-\frac{18}{2}x^{2}[/tex]

Answer 1

Answer:

To Find:-

• $-16x^{2}-\frac{18}{2}x^{2}$

Solution:-

$-16x^{2}-\frac{18}{2}x^{2} \\ \frac{ - 32 {x}^{2} }{2} - \frac{18 {x}^{2} }{2} \\ \frac{ - 32 {x}^{2} - 18 {x}^{2} }{2} \\ \frac{ - 50 {x}^{2} }{2} \\ = - 25 {x}^{2}$

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