Question

16x qube - 144x square
Factorise​

Answer 1

I hope it will help you

Answer 2

$Given \: 16x^{3} - 144x^{2}$

$= (16x^{2})\times x - (16x^{2})\times 9$

$= 16x^{2} ( x - 9 )$

Therefore.,

$\red{ 16x^{3} - 144x^{2}}$

$\green {= 16x^{2} ( x - 9 )}$

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