Question

16x2+24xy+9y2 slow this problem how to solve the problem

Answer 1

Simplifying 16x2 + 24xy + 9y2 = 0 Reorder the terms: 24xy + 16x2 + 9y2 = 0 Solving 24xy + 16x2 + 9y2 = 0 Solving for variable 'x'. Factor a trinomial. (4x + 3y)(4x + 3y) = 0

Subproblem 1

Set the factor '(4x + 3y)' equal to zero and attempt to solve: Simplifying 4x + 3y = 0 Solving 4x + 3y = 0 Move all terms containing x to the left, all other terms to the right. Add '-3y' to each side of the equation. 4x + 3y + -3y = 0 + -3y Combine like terms: 3y + -3y = 0 4x + 0 = 0 + -3y 4x = 0 + -3y Remove the zero: 4x = -3y Divide each side by '4'. x = -0.75y Simplifying x = -0.75y

Subproblem 2

Set the factor '(4x + 3y)' equal to zero and attempt to solve: Simplifying 4x + 3y = 0 Solving 4x + 3y = 0 Move all terms containing x to the left, all other terms to the right. Add '-3y' to each side of the equation. 4x + 3y + -3y = 0 + -3y Combine like terms: 3y + -3y = 0 4x + 0 = 0 + -3y 4x = 0 + -3y Remove the zero: 4x = -3y Divide each side by '4'. x = -0.75y Simplifying x = -0.75y

Solution

x = {-0.75y, -0.75y}

Answer 2

Heya !!!

$16 {x}^{2} + 24xy + 9 {y}^{2} \\ \\ 16 {x}^{2} = ({4x})^{2} \\ 9 {y}^{2} =( 3 {y})^{2} \\ 24xy = 2 \times 4 x\times 3y \\ use \: \: identity \: {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ \\ \\ \\ 16 {x}^{2} + 24xy + 9 {y}^{2} \\ = {(4x)}^{2} + 2 \times 4x \times 3y + {(3y)}^{2} \\ = {(4x)}^{2} + {(3y)}^{2} \\ = {(4 x+ 3y)}^{2}$



Hope it helps.