Question

16x²-42x+5 zeroes find

Answer 1

$\textbf{Answer :}$

$\textbf{Now,}$

$ 16x^2 - 42x + 5 $

$ = 16x^2 - (40 + 2)x + 5 $

$ = 16x^2 - 40x - 2x + 5 $

$ = 8x (2x - 5) - 1 (2x - 5) $

$ = (2x - 5) (8x - 1) $

$\textbf{Therefore, the required zeroes}$
$\textbf{are}$

$ x = 5/2, 1/8 $

#$\textbf{MarkAsBrainliest}$