17.1 gms of Al2(SO4)3 is present in 500 ml of Aqueous solution its concentration can be
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ans. is 0.01M
given wt. is 1.71 g
molecular wt. is 342 g
so ,mole = given wt / molecular wt.
= 1.71/342
=0.005moles
so concn= moles/volume
=0.005/0.5
=0.01M
given wt. is 1.71 g
molecular wt. is 342 g
so ,mole = given wt / molecular wt.
= 1.71/342
=0.005moles
so concn= moles/volume
=0.005/0.5
=0.01M
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