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17. 1
In AABC, AD I BC and AD2 = BC x CD,
prove that AABC is a right angled triangle.
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Answered by
24
Answer:
Pythagoras theorem should be apply ,
Then we have ,
AB² = AD² + BD² ----------(1)
AC²= AD²+ DC² ---------(2)
AB² + AC² = 2AD² + BD²+ DC²
= 2BD . CD + BD² + CD² [ ∵ given AD² = BD.CD ]
= (BD + CD )² = BC²
Thus in triangle ABC we have , AB² + AC²= BC²
hence triangle ABC is a right triangle right angled at A
∠ BAC = 90°
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1
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Check your answer please
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