Question

17. 1 mole of NO and 1 mole of O3 are taken in a 10 L
vessel and heated. At equilibrium, 50% of NO (by
mass) reacts with O3 according to the equation:
NO(g) + O3(g) (Reverse reaction) NO2(g) + O2(g).
What will be the equilibrium constant for this
reaction?
(a) 1 (b) 2 (c) 3 (d) 4​

Answer 1

Answer:. Option 2

I hope my answer will help you

Answer 2

Answer:

for the given reaction

                               NO (g) +  O₃ (g) ⇔ NO₂  (g) + O₂ (g)

initially                     1 M          1M            -                 -

at equilibrium         1-x             1-x         x                  x

        now we have 50% of NO

          50/100 x 1 =  1/2

      now we have Kc =  [O₂][NO₂] / [O₃][NO]

                        now insert the values     $\frac{1}{2} X \frac{1}{2} / \frac{1}{2} X \frac{1}{2} = 1$

hence option 1 is correct.