Question

17 (1)Triangle XYZ ~Triangle DEF. In triangle XYZ, XY = 5.1 cm, YZ = 3.9 cm, XZ = 6 cm.
XY: DE = 3 : 2. Construct AXYZ and A DEF....plz help me ​

Answer 1

$\triangle XYZ$ is the required triangle and $\triangle DFE$ is the another required triangle.

Step-by-step explanation:

Given,

$\triangle XYZ$≅$\triangle DFE$

$XY = 5.1\ cm, YZ = 3.9\ cm\ and\ XZ = 6\ cm$

And, $XY:DE=3:2$

⇒$DE=\frac{2(XY)}{3}$

⇒$DE=\frac{2\times 5.1}{3}$

⇒$DE=3.4\ cm$

And, $EF=3.9\ cm\ and\ DF=6\ cm$  (∵$\triangle XYZ$≅$\triangle DFE$)

Following steps:

• Draw a line segments $XY=5.1\ cm$ using scale.
• $X$ as center $6\ cm$ as radius draw an arc
• $Y$ as center $3.9\ cm$ as radius draw an arc which cuts the before arc at $Z$
• Join $XZ\ and\ YZ$

Now, $\triangle XYZ$ is the required triangle.

• Draw a line segments $DE=3.4\ cm$ using scale.

• $D$ as center $6\ cm$ as radius draw an arc
• $E$ as center $3.9\ cm$ as radius draw an arc which cuts the before arc at $F$
• Join $DF$ and $EF$

Hence,  $\triangle DFE$ is the another required triangle.

Answer 2

Step-by-step explanation:

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Step-by-step explanation:

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XY=5.1 cm,YZ=3.9 cm and XZ=6 cm

And,

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EF=3.9 cm and DF=6 cm (∵

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Following steps:

Draw a line segments

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△XYZ is the required triangle.

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