Question

17+[11-{8+3-(9 of 6+7-13×4)}]

Answer 1

start from small brakcet
(9 x 6+7-13x4)
( 54 +7 -52)
(9)
then large then small
[8+3-(9)]
[11-9]
[2]
then larger than large
[11-{2}]
[9]
then at outside
17+[9]
26 (ans )

HOPE IT WILL HELP YOU

Answer 2

17+[11-{8+3-(9 of 6+7-13×4)}]. BŌDMÆẞ
=17+[11-{8+3-(9 of 6+7-52)}]. B=Bræçkēt
=17+[11-{8+3-(9×6+7-52)}]. Œ=Øff
=17+[11-{8+3-(54+7-52)}]. M=Mūltìplïçãtīõñ
=17+[11-{8+3-(61-52)}]. Ã=Åddîtíòñ
=17+{11-(8+3-9)}. ẞ=ẞübtråçtìôñ
=17+{11-(11-9)}
=17+(11-2)
=17+9
=26
(ÆÑẞWĒR)