Question

17.1f 1 + sin? 0 = 3 sin 0 cos 0, then prove that tan 0 = 1 or
Or​

Answer 1

Step-by-step explanation:

$1 + \sin {}^{2} ( \alpha ) = 3 \sin( \alpha ) \cos( \alpha )$

Given - sin² a + cos² a = 1

$2 { \sin}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) = 3 \sin( \alpha ) \cos( \alpha )$

$2 \sin {}^{2} ( \alpha ) - 2 \sin( \alpha ) \cos( \alpha ) - \sin( \alpha ) \cos( \alpha ) + \cos {}^{2} ( \alpha )$

$2 \sin( \alpha ) ( \sin( \alpha ) - cos( \alpha ) + \cos( \alpha ) \sin( \alpha ) - \cos( \alpha )$

$\tan( \alpha ) = 1 or1 \div 2$