Question

[17(2-y)-5(y+12)]/1-7y=8

Answer 1

Step-by-step explanation:

17(2-y)-5(y+12)/1-7y=8

We move all terms to the left:

17(2-y)-5(y+12)/1-7y-(8)=0

We add all the numbers together, and all the variables

17(-1y+2)-5(y+12)/1-7y-8=0

We add all the numbers together, and all the variables

-7y+17(-1y+2)-5(y+12)/1-8=0

We multiply parentheses

-7y-17y-5(y+12)/1+34-8=0

We multiply all the terms by the denominator

-7y*1-17y*1-5(y+12)+34*1-8*1=0

We add all the numbers together, and all the variables

-7y*1-17y*1-5(y+12)+26=0

We multiply parentheses

-7y*1-17y*1-5y-60+26=0

Wy multiply elements

-7y-17y-5y-60+26=0

We add all the numbers together, and all the variables

-29y-34=0

We move all terms containing y to the left, all other terms to the right

-29y=34

y=34/-29

y=-1+5/29