Question

17 , 22 , 27 , 32 , The sum of first 20 term in the series is​

Answer 1

Sn = n/2(2a + (n_1)d

S = 20/2(2×17 +(20_1)5

ab kro solve ................. ...

Answer 2

Answer:

Here,

t1 = a = 17 & t2 = 22

So, d = t2 - t1 = 22 - 17 = 5

S20 = ?

We know,

$</strong><strong>S</strong><strong>n \: = \frac{n}{2} (2a + (n - 1)d) \\ </strong><strong>S</strong><strong>20 = \frac{20}{2}(2 \times 17 + (20 - 1)5 \\ </strong><strong>S</strong><strong>20 = 10(34 + 95) \\ </strong><strong>S</strong><strong>20 = 10 \times 129 \\ </strong><strong>S</strong><strong>20 = 1290$

Therefore,

Sum of first 20 terms is 1290.

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