17. 3.42 g sucrose are dissolved in 18 g of water in a beaker. The number of oxygen atoms in the
solution are
(a) 6.68 x 1029
(6) 6.09 x 1022
(c) 6.022 x 1023
(d) 6.022 X 1024
Answers
Answered by
2
Answer:
Molar mass of sucrose = 342 g
No. of oxygen atoms in 342 g of (C
12
H
22
O
11
) =11×N
A
∴ No. of oxygen atoms in 3.42 g of (C
12
H
22
O
11
) =
342
11×N
A
×3.42
= 0.11N
A
No. of oxygen atoms in 18g of H
2
O =1N
A
∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11N
A
+1N
A
=1.11N
A
=1.11×6.02×10
23
=6.68×10
23
.
Answered by
0
Answer:
6.68 x 1029
Explanation:
Molar mass of sucrose = 342 g
No. of oxygen atoms in 342 g of (C
12
H
22
O
11
) =11×N
A
∴ No. of oxygen atoms in 3.42 g of (C
12
H
22
O
11
) =
342
11×N
A
×3.42
= 0.11N
A
No. of oxygen atoms in 18g of H
2
O =1N
A
∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11N
A
+1N
A
=1.11N
A
=1.11×6.02×10
23
=6.68×10
23
.
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