Question

17
|300
M M
→ 5N
30%
BU
One end of a light inextensible string is attached to a fixed point A of a fixed vertical wire. The
other end of the string is attached to a small ring B, of mass 0.2 kg, through which the wire passes.
A horizontal force of magnitude 5 N is applied to the mid-point M of the string. The system is in
equilibrium with the string taut, with B below A, and with angles ABM and BAM equal to 30° (see
diagram)
(i) Show that the tension in BM is 5 N.
[3]
(ii) The ring is on the point of sliding up the wire. Find the coefficient of friction between the ring
and the wire.
[5]
(iii) A particle of mass m kg is attached to the ring. The ring is now on the point of sliding down the
wire. Given that the coefficient of friction between the ring and the wire is unchanged, find the
value of m.
[2]
Answers: ii) 0.932
iii) 0.466​

Answer 1

Answer:

sorry i don't know this answer but am trying to answer this question but i don't know