Question

17(34-17x)/1-7x + 5(x+12)/7x-1=8

Answer 1

17(2-x)-5(x+12)/1-7x=8
We move all terms to the left:
17(2-x)-5(x+12)/1-7x-(8)=0
We add all the numbers together, and all the variables
17(-1x+2)-5(x+12)/1-7x-8=0
We add all the numbers together, and all the variables
-7x+17(-1x+2)-5(x+12)/1-8=0
We multiply parentheses
-7x-17x-5(x+12)/1+34-8=0
We multiply all the terms by the denominator
-7x*1-17x*1-5(x+12)+34*1-8*1=0
We add all the numbers together, and all the variables
-7x*1-17x*1-5(x+12)+26=0
We multiply parentheses
-7x*1-17x*1-5x-60+26=0
Wy\e multiply elements
-7x-17x-5x-60+26=0
We add all the numbers together, and all the variables
-29x-34=0
We move all terms containing x to the left, all other terms to the right
-29x=34
x=34/-29
x=-1+5/29