17=6×2+5 is compared to Euclid division lemma a=bq+r then which number is remainder
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4
Answer:
5
Explanation:
In Euclid's division lemma
a=bq+r
r=remainder
we are given the equation
17=6*2+5
on comparing it with the above equation
we get
a=17
b=6
q=2
r=5
Therefore the remainder is 5
Hope this helps.
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