Question

17. A 5% (by mass) solution of glucose molar mass = 180 g mol-) is isotonic
with 1% solution (by mass) of a substance X. The molar mass of X is​

Answer 1

36 g

Explanation:

Given: molar mass of glucose = 180 g/mole,

% of glucose = 5 % means 5 g of solute present in 100 ml of solution

we know that For isotonic solution

π₁ = π₂ ⇒ c₁=c₂

5/180 = 1/M₂

M₂ = 180/5 = 36 g