Question

17. (a-b) 3 + (b -c) 3 + (c-a)3
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Answer 1

Answer:

(a-b)³+(b-c)³+(c-a)³ = 3ab(a-b)+3bc(b-c)+3ca(c-a)

Step-by-step explanation:

= a³-b³-3a²b+3ab²+b³-c³-3b²c+3bc²+c³-a³-3c²a+3ca²

= -3a²b+3ab²-3b²c+3bc²-3c²a+3ca²

= 3ab(a-b)+3bc(b-c)+3ca(c-a).