Math, asked by nampallyumadevi, 6 months ago

17.
A ball of mass 1 kg is thrown up. It reaches a maximum height of 5m. What is the work
done by the force of gravity during motion (g = 9.8 m/s)
1) 4.9 J
2) 6.9 J
3) 49 J
4) 9.​

Answers

Answered by harnoordhanju10
2

Answer:

Answer will come (-49)

Step-by-step explanation:

Work done by gravity = change in potential energy

=0−mgh

=−1×9.8×5=−49J

Answered by snowwhiteaug18
0

Answer:

3) 49 J

Step-by-step explanation:

Energy done by the force of gravity = Gravitational Potential Energy

Formula of Gravitational Potential Energy = mgh

In this case, m = 1 kg, g = 9.8 m/s and h = 5 m

The units are already in balance, therefore

mgh = 1 x 9.8 x 5 = 49

Hope this helped. Ugh, I still don't understand the FORCES chapter myself....so...teehee, good luck!

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