17.
A ball of mass 1 kg is thrown up. It reaches a maximum height of 5m. What is the work
done by the force of gravity during motion (g = 9.8 m/s)
1) 4.9 J
2) 6.9 J
3) 49 J
4) 9.
Answers
Answered by
2
Answer:
Answer will come (-49)
Step-by-step explanation:
Work done by gravity = change in potential energy
=0−mgh
=−1×9.8×5=−49J
Answered by
0
Answer:
3) 49 J
Step-by-step explanation:
Energy done by the force of gravity = Gravitational Potential Energy
Formula of Gravitational Potential Energy = mgh
In this case, m = 1 kg, g = 9.8 m/s and h = 5 m
The units are already in balance, therefore
mgh = 1 x 9.8 x 5 = 49
Hope this helped. Ugh, I still don't understand the FORCES chapter myself....so...teehee, good luck!
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