Question

17.A ball of mass 2 kg traveling at 8 ms strikes a ball of mass 4 kg
traveling at 2 ms. Both balls are moving along the same straight
line as shown.
2 ms-1
sms-1
2 kg
4 kg
2 kg
4 kg
After collision, both balls move at the same velocity v. What is the
magnitude of the velocity v?
-1
-1
A. 4 ms
B. 5 ms
6 ms
D. 8 ms
E. 10 ms -1​

Answer 1

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By using law of conservation of momentum

$m_{1} v_{1} + m _{2}v_{2} = m_{1}u_{1} + m_{2} u_{2}$

$(m_{1} + m _{2})v_{total} = m_{1}u_{1} + m_{2} u_{2}$

( 2+4 ) v = 2×8 + 4×2

6v = 16 + 8

6v = 24

v = 24 / 6

v = 4 m/s

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