Question

17. A body is moving with velocity of 3 m/s. Find
the distance travelled in 4 second is (1) its
velocity is constant (II) its acceleration is 2 m/s2
a) 12, 20
b) 12, 12
c) 12, 20
d) None
​

Answer 1

Explanation:

$velocity \: \: is \: \: constant \\ u = v = 3 \: \frac{m}{s} \\ s = find \\ t = 4 \: s \\ a = 0 \: \frac{m}{ {s}^{2} } \\ s = ut + \frac{1}{2} a {t}^{2} \\ s = 3 \times 4 + 0 \\ s = 12 \: meter \\ \\ accleration \: is \: 2 \frac{m}{ {s}^{2} } \\ \\ u = 0\\v = 3 \\ t = 4 \\ a = 2 \\ s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 + \frac{1}{2} \times 2 \times (4) {}^{2} \\ s = 16 \: meter$

Answer 2

Answer:

d)none

Explanation:

1) s=12m.(constant velocity)

2) s=28m (a=2)