17.A body is projected vertically upwards with velocity of 49 m/s. How much high will it rise? How
long will it be in air?
Ans. 122.5 m, 10 s
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Answer:
Hmax=122.5m T=10s
Hmax=u^2/2g
=49×49/2×9.8
=2401/19.6
=122.5m
T=2u/g
=2×49/9.8
=98/9.8
=10s
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