Question

17. A can complete a piece of work x in 10 days, B can
complete the same work in 20 days and C can
complete the same work in 25 days. If they take
40 days to complete a piece of work y, then in how
many days can C alone complete the work y?
(A) 65
(B) 76
(C) 95 (D) 190​

Answer 1

Answer:

A's 1 day's work =251​

Similarly, B's 1 day's work =201​

A's and B's together 1 day's work

251​+201​=1004​+1005​=1004+5​=1009​

Their 5 day's work together = 5 x 1 day's work

1−10045​=100100​−10045​=100100−45​=10055​

Now, this remaining work is done by B.

Let B takes x days to complete it.

201​×x=10055​⇒x=10055​×20⇒x=555​⇒x=11

Hence, B will finish the remaining work in 11 days

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