Question

17 A force of 16 N is used to rotate a circular wheel of
diameter 50 cm from rest about its axis. If there is no
friction and the angular acceleration produced is 2
rad/s2 the moment of inertia of the wheel about the
axis is:
A) 16 Kgm2
B 5Kgm2
C) 2 Kgm2
D) 8 Kgm2
E) 4Kgm2
​

Answer 1

Answer:

4 kg m²

Explanation:

Torque = Force × Perpendicular distance

= 16 N × 0.5 m

= 8 N m

Moment of inertia = Torque / Angular acceleration

= 8 N m / (2 rad/s²)

= 4 N m s² / rad

= 4 kg m²