Question

17. A ladder 17m long when set against the wall of a house just reaches a window
at a height of 15m from the ground. How far is the lower end of the ladder from
the base of the wall.​

Answer 1

$\large\mathbb\color{orange}{Refer\: Attachment}$

Answer 2

$\huge\mathfrak{{\fcolorbox{lime}{lime}{{\color{black}{Answer~~~~~~↓}}}}}$

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$\large\bold{To~find~:}$

The distance between the wall and the lower end of the ladder { i.e., the length of BC }

Here, we get a right ∆ABC

$\large\therefore\mathtt{AC^{2}=AB^{2}+BC^{2}}$ ( Pythagoras theorem )

$\large\mathtt{→BC^{2}=AC^{2}-AB^{2}}$

$\large\mathtt{→BC^{2}=17^{2}-15^{2}}$

$\large\mathtt{→BC^{2}=289-225}$

$\large\mathtt{→BC^{2}=64}$

$\large\mathtt{→BC={\sqrt{64}}}$

$\large\therefore\mathtt{BC={\underline{\underline{8m}}}}$

Hence, the distance between the wall and the lower end of the ladder is 8m

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$\huge\mathrm\color{lime}{Hope~it~helps..!!}$