Question

17) A man and his daughter have the same digits in their ages but in reverse. A year ago he was twice
as old as her. How old are they now?
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Answer 1

Answer:

10x+y - 12 = 2(10y+x-12)

10x + y - 12 = 20y + 2x - 24

10x - 2x = 20y - y - 24 + 12

8x = 19y - 12

Divide by 8

x = 19%2F8y - 12%2F8

x = 19%2F8y - 3%2F2

only one value for y gives an integer value for x, that is

y = 4

then

x = 19%2F8(4) - 3%2F2

x = 19%2F2 - 3%2F2

x = 9.5 - 1.5

x = 8

:

man: 84, Daughter 48

Answer 2

Answer:

Man= 84    Daughter 48

Step-by-step explanation: