Question

17. A man buys 18 comics and decides to divide them among his children in the
ratio of their ages. Their ages are 9 years, 6 years and 3 years. How many
comics will each child get?​

Answer 1

✬ Comics = 9 , 6 & 3 ✬

Step-by-step explanation:

Given:

• Total number of comics he bought is 18.
• Ages of his children are 9 years , 6 years and 3 years.

To Find:

• How many comics each of them will get ?

Solution: Let x be the common in given ratios of children ages. Therefore

• First child = 9x comics

• Second child = 6x comics

• Third child = 3x comics

∴ Total ratio = 9x + 6x + 3x

➙ Total ratio = 18x

Now , let's find the value of x.

$\implies{\rm }$ Total ratio = Total comics

$\implies{\rm }$ 18x = 18

$\implies{\rm }$ x = 18/18

$\implies{\rm }$ x = 1

So the number of comics each will get is

➯ First child = 9x = 9 × 1 = 9 comics

➯ Second child = 6x = 6 × 1 = 6 comics

➯ Third child = 3x = 3 × 1 = 3 comics

Hence, they will get 9 , 6 and 3 comics respectively.

Answer 2

❍  Given : A man buys 18 comics and decides to divide them among his children in the ratio of their ages. Their ages are 9 years, 6 years and 3 years.

❍  To Find : How many comics will each child get?

❍ Formula Used :

• Total Comics × One numeral of the ratio / sum of ratio

✬ Solution :-

• ☯ Ratio = 9:6:3

❒ Then, find the sum of the ratio,

• ☯ Sum = 9 + 6 + 3 = 18.

☯ 9 years boys share of comics,

• ➯ 9 / 18 × 18 = 9 comics.

☯ 6 years boys share of comics,

• ➯ 6 / 18 × 18 = 6 comics.

☯ 3 years boys share of comics,

• ➯ 3 / 18 × 18 = 3 comics.

★ Therefore,

✬ 9 years boys get ➯ 9 comics.

✬ 6 years boys get ➯ 6 comics.

✬ 3 years boys get ➯ 3 comics.

★ Hope it helps u ★