Question

17. A rectangular piece of land measures 0.8 km by 0.6 km. Each side is to be fenced with
three rows of wire. Find the length of the wire needed. If the cost of fencing is 50 per
metre. find the total cost of fencing the land.​

Answer 1

Question says that,

A rectangular land of dimensions 0.8km by 0.6km is to be fenced 3 times a wire.

1. Find the length of the wire to be fenced.
2. The cost of fencing at the rate of Rs.50 per metre.

Answer 1 :

We know that,

Required length of wire :

→ 3 times the perimeter of the land.

• Perimeter of the land is given by : 2(l + b)

Or,

Required wire :

→ 3{2( 0.8 + 0.6)}

→ 3{2(1.4)}

→ 3{2.8}

→ 8.4km.

The length of the wire is 8.4km.

Answer 2 :

Given rate

→ Rs.50 per metre

Or, total cost :

→ 50 × 8.4

→ Rs.420

Total cost of fencing is Rs.420

Answer 2

Question :

A rectangular piece of land measures 0.8 km by 0.6 km. Each side is to be fenced with

three rows of wire. Find the length of the wire needed. If the cost of fencing is 50 per

metre. find the total cost of fencing the land

Solution :

Given length of rectangle field = 0.8 km

breadth of rectangle field = 0.6 km

But we know that .

Perimeter of rectangle field = 2[l+b]

So putting the value given in question in this equation

=2[0.8+0.6]

Perimeter of field = 2.8

Length of wire = 3×2.8 = 7.4 km

Cost of fencing = 50× 7.4

= 370

More to explore :

• The area of a rectangle depends on its sides. Basically, the formula for area is equal to the product of length and breadth of the rectangle.

• Whereas when we speak about the perimeter of a rectangle, it is equal to the sum of all its four sides.

• Hence, we can say, the region enclosed by the perimeter of the rectangle is its area.

• But in the case of a square, since all the sides are equal, therefore, the area of the square will be equal to the square of side-length.

• Area of rectangle = Length x Breadth
• A = lb but p = 2(l+b)