Question

17 A stone is allowed to fall from the top of a tower 100 m hin
time another stone is projected ventials
upwas, das feron the ground with a velocity a 25m/s. calulée
when and where the two stones will meet.
and at the
Same​

Answer 1

Answer:

Let the stones meet at point A after time t.

For upper stone :

u′=0

x=0+21gt2

x=21×10×t2

⟹x=5t2 ............(1)

For lower stone :

u=25 m/s

100−x=ut−21gt2

100−x=(25)t−21×10×t2

⟹100−x=25t−5t2 ............(2)

Adding (1) and (2), we get

25t=100

⟹t=4 s

From (1),

x=5×42

⟹x=80 m

Hence the stone meet at a height of 20 m above the ground after 4 seconds.