Question

17. A tower 24 metres high, casts a shadow of 16 metres. The height of a
tree that casts a shadow of 12 metres is :*
O 8 metres
O 32 metres
O 18 metres
O 10 metres
Step by step please​

Answer 1

From the question it is given that,
Height of a tower PQ=15m
It’s shadow QR=24 m
Let us assume the height of a telephone pole MN=x
It’s shadow NO=16m
Given, at the same time,
△PQR∼△MNO
Therefore, PQ/MN=ON/RQ
15/x=24/16
By cross multiplication we get,
x=(15×16)/24
x=240/24
x=10
Therefore, height of pole =10m.
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Answer 2

Answer:

Step-by-step explanation:

height of tower = 24m

height of its shadow = 16m

24/16  =  x/12

where x = height of the tree

3/2 = x/12

x = 18m

height of tree is 18m

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