Question

17. A wire is in a rectangular shape of length 42 cm and breadth 26cm, if it is bent in the form of a square, what will be the measure of each side. Also find which shape encloses more area​

Answer 1

Step-by-step explanation:

Length of the rectangle = 40 cm

Breadth of the rectangle = 22 cm

Since same length of wire is used to form a rectangle and square, we can say that,

perimeter of square = perimeter of rectangle

4 × Side = 2 (Length + Breadth)

4 × Side = 2 (40 + 22)

4 × Side = 2 × 62

4 × Side = 124

Side = 124/4

Side of square = 31 cm

Area of square = side × side

= 31 cm × 31 cm

= 961 cm2

Area of rectangle = Length × Breadth

= 40 cm × 22 cm

= 880 cm2

Hence, square shape encloses more area.

Answer 2

$\large\bold\red{Solution:}$

Length of the rectangle = 40 cm

Breadth of the rectangle = 22 cm

Since same length of wire is used to form a rectangle and square, we can say that,

perimeter of square = perimeter of rectangle

4 × Side = 2 (Length + Breadth)

4 × Side = 2 (40 + 22)

4 × Side = 2 × 62

4 × Side = 124

Side = 124/4

Side of square = 31 cm

Area of square = side × side

= 31 cm × 31 cm

= 961 cm2

Area of rectangle = Length × Breadth

= 40 cm × 22 cm

= 880 cm2

Hence, square shape encloses more area.