Question

17. A wire is in the shape of a rectangle. Its length is 20 cm and breadth is 16 cm. If the same
wire is re-bent in the shape of a square, what will be the measure of each side?
​

Answer 1

Answer:

Given -

A wire is in the shape of a rectangle. Its length is 20 cm and breadth is 16 cm. If the same

wire is re-bent in the shape of a square, what will be the measure of each side?

‎ ‎

‎ ‎

To find -

The Perimeter of the rectangle and later the side of square.

‎ ‎

‎ ‎

Solution-

➼In the given question, the wire is in a shape of a rectangle, so we will first find the Perimeter of the wire.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

= 2(20+16)

=2(36)

=72cm

➼Now, in the above question, it is mentioned wire is antisipated into a square, which means the Perimeter of the rectangular and square wire is equal.

Perimeter of rectangle = Perimeter of square

So, now as we the know the Perimeter of the square, we will find it's sides.

Let the side be =x

$\color{black}\boxed{\colorbox{saffron}{Perimeter-4×side}}$

72=4×x

=72÷4=x

=x= 18 cm

‎ ‎

‎ ‎

Required Answer -

$\rightarrow$ side of square = 18cm