Question

17. ਦਿੱਤੇ ਚਿੱਤਰ ਵਿੱਚ ਰੇਖਾਵਾਂ AB ਅਤੇ CD ਬਿੰਦੂ
0ਤੇ ਕੱਟਦੀਆਂ ਹਨ ਜੇਕਰ LAOC+BOE
=70° ਹੈ ਅਤੇ BOD =40°, ਤਾਂ, ZCOE ਪਤਾ
adi In fig. given Line AB and CD
intersect at O. If ZAOC + BOE =70°
and BOD =40°, Find ZCOE . ਵਿਚ ਗy
ਬਿਕ , ਦੇਗ AB ਕ CD, 0 ਧ ਲਾਟਰੀ ਫੈ। ਧਰਿ
ZAOC + LBOE =70° 311 _BOD =40°
ਫੈ, ਗੇ /COE ਧਗ ਦੇ ।*
E​

Answer 1

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

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