17. ΔABC is an isosceles triangle. Median AM is drawn to base BC. If A(ΔABC) = 30 sq cm, then what is A(ΔAMC)?
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Step-by-step explanation:
ABC is an isosceles triangle
AB = AC = 17 cm
BC = 16 cm
AG is the median
=> G is the mid point of BC
=> BG = CG = BC/2 = 16/2 = 8 cm
AG ⊥ BC ( as AB = AC)
=> AB² = BG² + AG²
=> 17² = 8² + AG²
=> AG² = Answer:please 289 - 64289 - 64
=> AG² = 225
=> AG = 15 cm
Length of Median AG = 15 cm
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