17. ABC is right angled at A (Fig 11.25). AD is perpendicular to BC. ITAB -5cm,
BC = 13 cm and AC = 12 cm. Find the area of AABC. Also find the length of
AD
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area of triangle ABC = 30cm2
length of AD = 60/13 cm
Step-by-step explanation:
(I) area of AABC =1/2×h×b
=1/2×6×12
=30cm2
(II) area of AABC =1/2×b×h
30 =1/2×13×AD
30×2 =13×AD
60/13=AD
Ans:- (I) area of AABC = 30cm2
(II) length of AD is 60/13cm
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