Question

17) ABCD is a rectangle where diagonals AC
and BD intersect at 0. Prove that triangles
AOB and COD are congruent.​

Answer 1

Answer:

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Answer 2

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Given:- AB=DC,∠AOD=∠DOC,AB║DC

R.T.P:- ΔAOB≅ΔDOC

Proof:-

In ΔAOB and ΔCOD

∠AOB=∠DOC  (Vertically oppposite angles)

∠OAB=∠OCD  ( AB║ DC and  AC is a transversal)

AB=DC (Given)

By AAS congruency  ΔAOB≅ΔCOD

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