Physics, asked by sahilshukla036, 8 months ago


17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1. Calculate the force on the particle

Ans. 4.8 x 10^-14N​

Answers

Answered by Anonymous
0

Given that ,

Charge (q) = 2e = 3.2 × (10)^-19 C

Electric field (E) = 15 x 10^4 N/c

As we know that ,

The electric force per unit charge is called electric field

Mathematically ,

  \large \sf\fbox{Electric  \: field \: ( E) =  \frac{F}{q} }

The SI unit of electric field is N/c

Thus ,

F = 15 x 10^4 × 3.2 × (10)^-19

F = 48 × (10)^-15

F = 4.8 × (10)^-14 N

  \therefore\sf \underline{The  \: electric \:  force  \: is  \: 4.8 \times  {(10)}^{ - 14}  \: N}

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