17. An electric heater of resistance electric heater of resistance 8 ohm draws 15 A from the service mains 2 hours Calculate the rate at which heat is developed in the heater Explain the following.
ending answer 120W
please help
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Answer:
Explanation:
R= 8ohm , I= 15A , T= 2hr
V= IR. (Ohm's law)
V= 15×8
V= 120volts
Now,
P= VI
P= 120×15
P= 1800 watt (W)
Used for 2 hour for 30 days
= 1800×2/1000
= 3.6 × 30
= 108 kWh
To find cost for rupees 5 per unit
= 108×5
= ₹540
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