Question

17. At 25°C length of a metal rod is 10m and its area of cross section is 50cm
Calculate the temperature at which it can have the same length as the length
obtained by a longitudinal force 4 x 10^N (Y = 2 x10'N/m², a = 12 x 10-6/K)
2) 28.33°C
3) 60°C
4) 50°C
1) 52°C
​

Answer 1

Answer:

The answer is 50°C because of its the

Explanation:

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Answer 2

The temperature is 52°C

Suppose, the temperature at which the lengths will be same is = T

Initial temperature = 25°C

Initial length of the rod is (L) = 10 m

The area of cross section is (A) = 50 cm²

                                                    = 50 × 10⁻⁴ m²

The value of the longitudinal force is (F) = 4 × 10 N

Y = 2 × 10 N/m²

α = 12 × 10⁻⁶ /K

If the final length is same, then the elongation in length will also be same.

l = YAαT

And, l = FL/AY

As both are same,

YAαT = FL/AY

∴ T = FL/A²Y²α

By calculating this, we get the value of temperature is 52°C.